CBSE Class 11-science Answered
if momentum increase 50% what is increase in kinetic energy?
Asked by | 02 Sep, 2009, 09:00: PM
Expert Answer
Pf = 1.5Pi
Ekf = Pf2/2m
= 1.5Pi2/2m
= 2.25Pi2/2m
= 2.25Eki
Percentage increase in kinetic energy = (Ekf - Eki)x100/Eki = 125%
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Answered by | 02 Sep, 2009, 09:08: PM
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