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if momentum increase 50% what is increase in kinetic energy?

Asked by 2nd September 2009, 9:00 PM
Answered by Expert
Answer:

Pf = 1.5Pi

Ekf = Pf2/2m

= 1.5Pi2/2m

= 2.25Pi2/2m

= 2.25Eki

Percentage increase in kinetic energy = (Ekf - Eki)x100/Eki = 125%


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TopperLearning.

 

Answered by Expert 2nd September 2009, 9:08 PM
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