If k+1,3k and 4k+1 be any three consecutive terms of an A.P find the value of k.
Asked by Ramond Williem MDcs25th January 2014, 11:05 AM
Answered by Expert
This is very easy!
The given A.P is k + 1, 3k and 4k + 1
Since it is an A.P, The common difference between two consequent terms will be equal.
Therefore 3k - (k + 1) = (4k + 1) - 3k
3k - k - 1 = 4k - 3k + 1
2k - 1 = k + 1
2k - k = 2
Therefore k = 2
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