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If k+1,3k and 4k+1 be any three consecutive terms of an A.P find the value of k.

Asked by Ramond Williem MDcs 25th January 2014, 11:05 AM
Answered by Expert
Answer:
Hi Raymond, This is very easy! The given A.P is k + 1, 3k and 4k + 1 Since it is an A.P, The common difference between two consequent terms will be equal. Therefore 3k - (k + 1) = (4k + 1) - 3k 3k - k - 1 = 4k - 3k + 1 2k - 1 = k + 1 2k - k = 2 Therefore k = 2
Answered by Expert 29th January 2014, 4:41 PM
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