CBSE Class 10 Answered
If k+1,3k and 4k+1 be any three consecutive terms of an A.P find the value of k.
Asked by Ramond Williem MDcs | 25 Jan, 2014, 11:05: AM
Expert Answer
Hi Raymond,
This is very easy!
The given A.P is k + 1, 3k and 4k + 1
Since it is an A.P, The common difference between two consequent terms will be equal.
Therefore 3k - (k + 1) = (4k + 1) - 3k
3k - k - 1 = 4k - 3k + 1
2k - 1 = k + 1
2k - k = 2
Therefore k = 2
Answered by | 29 Jan, 2014, 04:41: PM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by yalagondanikhil | 16 Apr, 2024, 12:25: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by rrajansinghakb199 | 08 Apr, 2024, 05:12: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by nagalaxmidurgarao937 | 08 Apr, 2024, 01:42: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mraniruddha03 | 02 Apr, 2024, 06:44: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by muttenenimalleswarrao | 29 Mar, 2024, 08:32: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by pathakvaishnavi9139 | 23 Mar, 2024, 10:45: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mustafahssn786 | 23 Mar, 2024, 06:25: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by choudharyniki001 | 22 Mar, 2024, 08:49: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by jagdishdabang79 | 18 Mar, 2024, 08:40: PM
ANSWERED BY EXPERT