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if hydrogen atom is excited by giving 8.4eV energy then number of emitted spectral lines wil be?

Asked by shaikh sameer 15th October 2013, 10:20 AM
Answered by Expert
Answer:

   E 1/n2

 For n=1, E = 13.6 eV

Thus energy absorbed =13.6 (1 - (1 / n2) eV., where n =1 to

For n=2, E = 13.6(1 - (1 / 22) = 10.2

This is the lowest energy state possible for emission of spectral lines.

Thus the energy absorbed should always be between 10.2 and 13.6 eV

Hence , no emission takes place when  hydrogen atom is excited by giving 8.4eV.

Answered by Expert 15th October 2013, 11:40 AM
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