CBSE Class 10 Answered
if hcf of 210 and 55 is expressible in the form 210×5-55x, find x
Asked by harshvsk05 | 03 Apr, 2020, 11:59: AM
Expert Answer
210 = 55 × 3 + 45 ... (1)
55 = 45 × 1 + 10 ... (2)
45 = 10 × 4 + 5
10 = 5 × 2 + 0
HCF(210, 35) =5 = 210×5-55x
5 = 45 - 10 × 4
= 210 - 55 × 3 - (55 - 45)4 .... from (1) and (2)
= 210 - 55 × 3 - 55 × 4 + 45