If E is the kinetic energy of the particle then which of the following expressions is correct for de - Broglie wavelength of the particle a) lamda=h÷2mE. b) lamda=√h÷2mE. c)lamda=h÷√2mE. d)lamda=√2mE÷h
Asked by athmakiranvinay
17th August 2016,
8:39 PM
Answered by Expert
Answer:
Correct option is C
Answered by Expert
18th August 2016,
1:19 PM
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