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If E is the kinetic energy of the particle then which of the following expressions is correct for de - Broglie wavelength of the particle          a) lamda=h÷2mE.      b) lamda=√h÷2mE.          c)lamda=h÷√2mE.          d)lamda=√2mE÷h

Asked by athmakiranvinay 17th August 2016, 8:39 PM
Answered by Expert
Answer:
Correct option is C
 
Answered by Expert 18th August 2016, 1:19 PM
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