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CBSE Class 10 Answered

If d is the H.C.F. of 45 and 27,findx and y satisfying d=27x+45y
Asked by Ckmjoseph17 | 30 Mar, 2019, 05:48: AM
answered-by-expert Expert Answer
45 = 3×3×5
27 = 3×3×3
 
hence HCF of 45 and 27 is 3×3 or 9
 
d = 27x +45y
 
9 = 27x +45y
 
dividing both sides by 9 , 3x+5y = 1
Thus, x=2, y=-1 is the solution of above equation
x=7, y=-4 is the solution
Thus, x can take values 2, 7, 12, 17, 22,... and y=-1, -4, -7, -10, -13,....
Answered by Renu Varma | 30 Mar, 2019, 08:43: AM

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