If a copper wire is stretched to make it a cross-sectional radius 0.1% thinner than what is the percentage increase the resistance
Asked by 2238750243078948
31st August 2018,
6:02 PM
Answered by Expert
Answer:
Resistance R = 
...............(1)
...............(1)where ρ is resistivity of the material of the wire, L is length, A is crosssection area and r is radius.
C is constant because length and resistivity are not changed due to stretching of wire
By taking logarithm on both sides of (1), we get, ln R = ln C - 2 ln r ............(2)
by diferentiating (2), we get, 
Hence resistance decrese by 0.2%
Answered by Expert
2nd September 2018,
6:58 AM
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