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CBSE Class 11-science Answered

If a body is projected at the angle of 45degree with a velocity of 20m/sec.Find it's height reached when it covers a distance of 15m in horizontal.
Asked by surjan06singh | 13 Aug, 2019, 08:04: PM
answered-by-expert Expert Answer
Horizontal velocity component = 20×cos45 m/s = 20×(1/√2) = 10√2 m/s
 
time taken t to travel 15 m is given by,   t = 15/(10√2) = (3/4)√2 s
 
vertical distance h travelled in a time t = (3/4)√2 s is given by, 
 
h = u×sinα×t - (1/2)g t2 = 20×sin45×(3/4)√2 -(1/2)×9.8×[(3/4)√2]2 ≈ 9.5 m
Answered by Thiyagarajan K | 13 Aug, 2019, 09:44: PM
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