if a=2x; initally particle is at x=2m and is moving with 3m/s then find out v at x=5m
Asked by gargpuneet989
25th June 2018,
5:45 PM
Answered by Expert
Answer:
Given acceleration a(x) = 2x is function of position.
let us integrate acceleration a(x) from x=2 to x=5, 
J/kg....................(1)
J/kg....................(1)Eqn(1) can be viewed as Workdone on a unit mass by a variable force from x=2 to x=5 .
Workdone will change the kinetic energy. Hence 
J/kg .............(2)
J/kg .............(2)where vf is final velocity at x=5 and vi is initial velocity at x=2. Unit mass is assumed in eqn.(2)
By substituting vi = 3 m/s in eqn(2), we get 
Answered by Expert
25th June 2018,
10:48 PM
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