CBSE Class 10 Answered
Let A(3,3), B(6, y), C(x, 7) and D (5, 6) be the vertices of parallelogram ABCD.
We know that, diagonals of parallelogram bisect each other.
=> Coordinate of mid point of diagonal BD = Coordinate of mid point of diagonal AC
Coordinates of mid point of diagonal BD = (5+6 )/2 , (6+y) /2
= 11/2 , (6+y)/2
Coordinate of mid point of diagonal AC = (3+x)/2 , (7+3)/2
= (3+x)/2 , 10/2
Now comparing the c xordinates of mid point of both diagnols
=> 11/2 = (3+x)/2
=> 11 = 3+ x
=> x = 8
similarily comparing y coordinates
=> (6+y)/2 = 10/2
=> 6+ y = 10
=> y = 4
=> Answer : x =8 and y = 4