If 1,w,w^2 are the roots of unity then show that
(P+qw+rw^2)/(r+pe+qw^2)=w^2
Asked by tamasiganguly66
28th August 2020,
2:37 PM
Answered by Expert
Answer:
As 1,w,w2 are the cube roots of unity, we have
w3 = 1 i.e. (w-1)(w2+w+1)=0
As w is not equal to 0, so we have w2+w+1 = 0
Now use this to prove (p+qw+rw2)/(r+pw+qw2)=w2
Answered by Expert
1st September 2020,
1:40 PM
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