CBSE Class 9 Answered
(i)Side BC of
is produced to a point D.The bisector of 
meets BC at L.Prove 
.
is produced to a point D.The bisector of meets BC at L.Prove .(ii)A point O is taken inside an equilateral four sided figure ABCD such that its distances from the angular points D & B are equal.Show that AO & OC are in one & the same straight line.
Asked by araima2001 | 13 Sep, 2014, 11:00: AM
Expert Answer
In given equilateral four sided figure ABCD
AD = AB (
equilateral quadrilateral)
AO = AO (common)
OD = OB (Given)
Therefore , 
AOD = AOB ……………..(1)
Similarly , CDO = BOC ……………...(2)
But, AOD + AOB + CDO + BOC = 360
2 AOB + 2 BOC = 360 (From eqn (1) and (2) )
2 ( AOB + BOC )= 360
AOB + BOC = 180
So, AO and OC are in same straight line
Hence proved
Answered by Dharma Teja | 14 Sep, 2014, 11:35: PM
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