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# I am getting confused in the circuits. Please explain you your method and approach thoroughly so I can get it. thank you.

Asked by Arushi Juyal 12th December 2017, 7:01 AM
Refer the figure to get the current i flowing in the circuit as given below

(1+2+2)×i + 8 + 5×i = 20

hence i = 1.2 A

Equivalent resistance of 3 resistive coils is 2 Ω and current passing through all of them is 1.2 A.

Hence the potential difference across the three combined resistive coils is 2×1.2 = 2.4V

Hence the current passing through the 12 Ω coil is 2.4/12 = 0.2A = 200 mA

Here 20V battery is delivering the required current in the circuit. hence the drop in potential difference across the internal resistance 1Ω is 1×1.2 = 1.2V

Hence potential difference across 20V battery is 20-1.2=18.8V

second battery is not delivering any current, hence 8V is the potential difference across the second battery
Answered by Expert 12th December 2017, 7:00 PM
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