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 how zncl2 help in prepration of haloalkanes in groove process?

Asked by gargimoitreyee 17th March 2018, 11:09 AM
Answered by Expert
Answer:

Role of anhydrous ZnCl2:

It helps cleave the C–O bond. Being a Lewis acid, it coordinates with the oxygen

atom of the alcohols. This result in weakening of the C–O bond which ultimately

breaks to form carbocations.

Answered by Expert 17th March 2018, 12:30 PM
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