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How would you make up 425ml of 0.15M HNO3 from nitric acid that is 68% HNO3 ? The density of 68% HNO3 is 1.41g/ml.

Asked by kumar19raj98 25th July 2019, 10:41 PM
Answered by Expert
Answer:
Given:
 
Volume = 425 ml
 
            = 0.425 L
 
Molarity = 0.15 M
 
Density = 1.41 g/ml
 
We know,
 
Molarity 
 
equals fraction numerator No. space of space moles over denominator Volume space in space straight L end fraction

No. space of space moles equals 0.15 cross times 0.425 space

space space space space space space space space space space space space space space space space space space space space equals space 0.06375 space mole
 
No. of moles 
 
equals fraction numerator Weight over denominator Molecular space weight end fraction

Weight space equals space 0.06375 cross times 63

space space space space space space space space space space space space equals space 4.01 space gm
 
 
Density 
 
 
equals fraction numerator Mass space over denominator Volume end fraction
 
For 4.01 gm, the volume will be
 
equals fraction numerator 4.01 cross times 1 over denominator 1.41 end fraction

equals space 2.84 space ml
 
2.84 ml of HNO3 is dilutes to 425 ml to make 0.15 M solution.
Answered by Expert 26th July 2019, 11:15 AM
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