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Asked by pukai7229 29th October 2018, 9:44 PM
Answered by Expert
Answer:
When A and B are mixed, A gains heat energy and B looses heat energy to reach a common temperature.
 
Heat Gain by A = Heat Loss by B
 
CA×4 = CB×3    or  CA = (3/4)×CB ............(1)
 
where CA , C is specific heat of A and B respectively.
 
When B and C are mixed, B gains heat energy and C looses heat energy to reach a common temperature.
 
Heat Gain by B = Heat Loss by C
 
CB×4 = CC×5    or  CC = (4/5)×CB ............(2)
 
When A and C are mixed, A will gain heat energy and C will loose heat energy to reach a common temperature T
 
Then we have, CA × ( T - 12)  = CC×(28-T)  ................(3)
 
using (1) and (2), we rewrite eqn.(3) and simplify as, (3/4) × ( T - 12)  = (4/5)×(28-T) .....................(4)
 
from (4), we get T = 20.3 ºC
Answered by Expert 30th October 2018, 1:57 AM
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