Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

How to solve 

Asked by amitjena226 21st December 2017, 10:40 PM
Answered by Expert
Answer:
As per benouli's equation P+(1/2)ρv2 is constant. 
 
Hence pressure difference between top and bottom surfaces of wing is
 begin mathsize 12px style 1 half rho open parentheses v subscript t superscript 2 minus v subscript b superscript 2 close parentheses space equals space 1 half cross times 1.28 cross times open parentheses 140 squared minus 110 squared close parentheses space equals space 4800 space N divided by m squared
f o r c e space equals space 4800 cross times 10 space equals space 48000 space N end style
Answered by Expert 22nd December 2017, 12:00 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!
NEET QUESTION ANSWERS

Chat with us on WhatsApp