Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Enquiry (North & South)

Business Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

How to solve this question?

qsnImg
Asked by pratham.k 30th June 2020, 9:09 PM
Answered by Expert
Answer:
A block of mass m is attached to one end of a light string is wrapped on a disc of mass 2m and Radius R. The total length of the
slack portion of the string is l. The block is released from rest. The angular velocity of the disc just after the string becomes taut is
v e l o c i t y space o f space t h e space b l o c k space w h e n space i t space r e a c h e s space b o t t o m space a n d space s t r i n g space b e c o m e s space s t r a i n g h
v squared equals u squared plus 2 a s
v squared equals 0 squared plus 2 g l
v equals square root of 2 g l end root
A n g u l a r space m o m e n t u m space o f space t h e space m a s s space w h e n space t h e space s t r i n g space b e c o m e s space s t r a i g h t
equals m square root of 2 g l end root R
A n g u l a r space m o m e n t u m space w i l l space r e m a i n space c o n s e r v e d space
a s space a space r e s u l t space a n g u l a r space m o m e n t u m space o f space t h e space d i s c
equals I omega
m square root of 2 g l end root R equals fraction numerator 2 m R squared over denominator 2 end fraction omega
omega equals fraction numerator square root of 2 g l end root over denominator R end fraction
Answered by Expert 2nd July 2020, 11:54 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp