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# how to solve the problems of linear equation?

Asked by Ajay G. 4th April 2017, 7:24 PM

Steps to solve a linear equation:

● Transfer all the x terms (that is all variable terms) on one side, and keep the numbers

to the other side.

● Simplify each side and solve for x.

● Verify to be sure whether the answers satisfy the original equations.

Example:

Solve the equation 6(3x + 2) + 5(7x - 6) - 12x = 5(6x - 1) + 6(x - 3) and verify your answer

Solution:

6(3x + 2) + 5(7x - 6) - 12x = 5(6x - 1) + 6(x - 3)

⇒ 18x + 12 + 35x - 30 - 12x = 30x - 5 + 6x - 18

⇒ 18x + 35x - 12x + 12 - 30 = 30x + 6x - 5 - 18

⇒ 41x - 18 = 36x - 23

⇒ 41x - 36x = - 23 + 18

⇒ 5x = -5

⇒ x = -1

Therefore, x = -1 is the solution of the given equation.

Verification:

L.H.S. = 6(3x + 2) + 5(7x - 6) - 12x

Substitute the value of x = -1 we get;

= 6[3 × (-1) + 2] + 5 [7 × (-1) - 6] - 12 × (-1)

= 6[-3 + 2] + 5[-7 - 6] + 12

= 6 × (-1) + 5 (-13) + 12

= - 6 - 65 + 12

= -71 + 12

= -59

Verification:

R.H.S. = 5(6x - 1) + 6(x - 3)

Substitute the value of x = - 1, we get

= 5[6 × (-1) - 1] + 6[(-1) - 3]

= 5(-6 - 1) + 6(-1 -3)

= 5 × (-7) + 6 × (-4)

= - 35 - 24

= - 59

Since, L.H.S. = R.H.S. hence verified.

Answered by Expert 5th April 2017, 9:44 AM

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## Solution of accountancy ch4 accounting ratios

Asked by 372383669838357 21st March 2018, 5:27 AM

## (3)  Find the point ( p,q) on the ellipse 4x^2  + 3y^2  = 12 , in the first quardent . so that the area enclosed by the lines  y = x ,  y = q , x = p , x - axis is maximum.

Asked by sudhanshubhushanroy 20th March 2018, 10:18 PM

## (2) Find the values of   p  for which three distinct chords drawn from  ( p,0 ) to the ellipse   x^2  +  2y^2  =  1  are bisected by the parabola y^2  = 4x.

Asked by sudhanshubhushanroy 20th March 2018, 10:13 PM