NEET Class neet Answered
How to solve Q63
Asked by tps.mjmdr | 16 May, 2019, 10:24: PM
Expert Answer
let masses of wire be m, 3m, 5m and their lengths be 5l, 3l, l.
if ρ is density of copper and a1, a2, a3 are cross section area of wires,
we have m = ρ×a1×5l .................(1)
3m = ρ×a2 ×3l ..............(2)
5m = ρ×a3×l ................(3)
then ratio of a1 : a2 :a3 = (1/5) :1 : 5 or a1 : a2 :a3 = 1 : 5 : 25
hence we consider crosssection areas are a, 5a, 25a
Resistance ratio = (5l/a) : (3l/5a) : (l/25a) = 125 : 15 : 1
Answered by Thiyagarajan K | 17 May, 2019, 05:54: AM
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