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how to solve 2nd part

Asked by lakshyasaxena970 7th July 2021, 10:42 PM
Part (a)

As shown in figure , Train-B has to travel a distance 500 m to overtake Train-A .

Relative velocity of Train-B with respect to train-A is (40-20) = 20 m/s .

Hence time taken to travel 500 m distance = distance / relative velocity = 500 / 20 = 25 s

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Part (b)

Required acceleration a for train-B to overtake train-A in a time duration of t seconds is determined
from the following equation of motion

S = [ uB - uA ] t + (1/2) a t2

Where S is distance to be travelled, uA is the initial speed of train-A  and uB is initial speed of train-B

Since both train are moving with same speed ,  [ u- uA ] = 0

Hence , we have ,  S = (1/2) a t2   or      a   = ( 2 S ) / t2

acceleration a = ( 2 × 500 ) / (50 × 50 ) = 0.4 m/s2
Answered by Expert 8th July 2021, 8:32 AM
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