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how to solve    1/√7-√6
solve with defination

Asked by rehanahmadxlx 31st May 2016, 10:23 PM
Answered by Expert
Answer:
begin mathsize 12px style fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction
T o space r a t i o n a l i s e space t h e space d e n o m i n a t o r comma space w e space m u l t i p l y space b o t h space n u m e r a t o r space a n d space t h e space d e n o m i n a t o r
b y space square root of 7 plus square root of 6

fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 minus square root of 6 close parentheses open parentheses square root of 7 plus square root of 6 close parentheses end fraction
equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 close parentheses squared minus open parentheses square root of 6 close parentheses squared end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 7 minus 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 1 end fraction
equals square root of 7 plus square root of 6 end style
Answered by Expert 1st June 2016, 11:24 AM
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