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CBSE Class 9 Answered

how to solve    1/√7-√6
solve with defination
Asked by rehanahmadxlx | 31 May, 2016, 10:23: PM
answered-by-expert Expert Answer
begin mathsize 12px style fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction T o space r a t i o n a l i s e space t h e space d e n o m i n a t o r comma space w e space m u l t i p l y space b o t h space n u m e r a t o r space a n d space t h e space d e n o m i n a t o r b y space square root of 7 plus square root of 6 fraction numerator 1 over denominator square root of 7 minus square root of 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 minus square root of 6 close parentheses open parentheses square root of 7 plus square root of 6 close parentheses end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator open parentheses square root of 7 close parentheses squared minus open parentheses square root of 6 close parentheses squared end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 7 minus 6 end fraction equals fraction numerator square root of 7 plus square root of 6 over denominator 1 end fraction equals square root of 7 plus square root of 6 end style
Answered by satyajit samal | 01 Jun, 2016, 11:24: AM

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CBSE 9 - Maths
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