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How to find electronic configuration of atoms? Give the full study materials.

Asked by Tony Innocent 25th October 2013, 2:15 PM
Answered by Expert
Answer:

To find electronic configuration of atoms, you should know its atomic numbers.

 

For electronic configuration of elements, the most important thing that you should be aware of -

The order in which orbitals of different subshells are filled. We know that this order is determined by the (n + l) rule and is as follows:

 

Order for filling subshells: 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p 

where the number indicates the energy level and the letter indicates the subshell being filled.

Maximum number of electrons in each subshell: s=2, p=6, d=10, f=14 

A superscipt number after the letter of the subshell shows how many electrons occupy that subshell.

The helium atom has 2 electrons, both in the s subshell of the first energy level. 
Its sub-shell electron configuration is 1s2

The neon atom has 10 electrons. 
2 electrons in the s subshell of the first energy level: 1s2 
8 electrons in second energy level, made up of 2 electrons in an s subshell and 6 electrons in a p subshell: 2s2 2p6 
Its subshell electron configuration is 1s2 2s2 2p6

The argon atom has 18 electrons. 
2 electrons in the s sub-shell of the first energy level: 1s2 
8 electrons in the second energy level made up of 2 electrons in an s subshell and 6 electrons in a p subshell: 2s2 2p6 
8 electrons in the third energy level made up of 2 electrons in an s subshell and 6 electrons in a p subshell: 3s2 3p6 
Its subshell electron configuration is: 1s2 2s2 2p6 3s2 3p6

Table showing examples of electronic configuration of atoms and ions are as follows:

Atom

Z

No. Electrons
= Z

Subshell Electron Configuration

Ion

No. Electrons
= Z - charge

Subshell Electron Configuration

H

1

1

1s1

H-

1 - (-1) = 2

1s2

He

2

2

1s2

 

 

 

Li

3

3

1s2 2s1

Li+

3 - 1 = 2

1s2

Be

4

4

1s2 2s2

Be2+

4 - 2 = 2

1s2

B

5

5

1s2 2s2 2p1

B3+

5 - 3 = 2

1s2

C

6

6

1s2 2s2 2p2

C4+

6 - 4 = 2

1s2

N

7

7

1s2 2s2 2p3

N3-

7 - (-3) = 10

1s2 2s2 2p6

O

8

8

1s2 2s2 2p4

O2-

8 - (-2) = 10

1s2 2s2 2p6

F

9

9

1s2 2s2 2p5

F-

9 - (-1) = 10

1s2 2s2 2p6

Answered by Expert 26th October 2013, 11:15 PM
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