How to do this
Asked by pukai7229
2nd November 2018,
11:03 PM
Answered by Expert
Answer:
Heat gained by 0.15kg of Ice at 0°C to become water at 6.7°C = 0.15×L +0.15×4.186×103 × 6.7 = 0.15×L+4.207×103 J .............(1)
where L is latent heat of fusion of ice.
Heat lost by 0.3 kg of water from 50°C to 6.7°C = 0.3×4.186×103 ×(50-6.7) = 54.376×103 J........................(2)
By conservation of energy, Heat Loss and heat gain are equal.
Hence we can equate eqn(1) and (2), we get, 0.15×L+4.207×103 = 54.376×103 .......................(3)
By solving eqn.(3), we get L = 3.34×105 J
Answered by Expert
3rd November 2018,
2:58 AM
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