Request a call back

Join NOW to get access to exclusive study material for best results

ICSE Class 10 Answered

How many terms of the A P 17,15,13,11..... must be added to get the sum 72?
Asked by suneelmsc | 29 Jun, 2020, 04:59: PM
answered-by-expert Expert Answer
In this AP, we are given a = 17, d = -2, Sn = 72 and we have to find n
Sum of first n terms = n/2[2a+(n-1)d]
Sum is given as 72
72 = n/2[2 x 17 + (n - 1)(-2)]
144 = n[34-2n+2]
144 = n[36-2n]
72 = n(18 - n)
n2 - 18n + 72 = 0
n2 - 12n - 6n + 72 = 0
n(n - 12) - 6(n - 12) = 0
(n - 12)(n - 6) = 0
=> n = 6, 12
Both values of n, being positive integers are valid. We get double answer because sum of 7th to 12th terms is zero, as some terms are positive and some are negative
Answered by Renu Varma | 29 Jun, 2020, 08:05: PM

Concept Videos

ICSE 10 - Maths
Asked by srilakshmivytla28 | 10 Sep, 2023, 09:19: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by rashikulkarni28 | 14 Aug, 2022, 04:32: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by rashikulkarni28 | 14 Aug, 2022, 04:30: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by arpitadas4117 | 17 Jan, 2022, 02:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by savithakotari962 | 08 Feb, 2021, 08:40: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by ruchitripathi96167 | 22 Sep, 2020, 12:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
ICSE 10 - Maths
Asked by suneelmsc | 29 Jun, 2020, 05:00: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×