Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

10:00 AM to 7:00 PM IST all days.

Business Enquiry (North)

Business Enquiry (South)

Business Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

How many optically active stereoisomers are possible for butan-2,3-diol?

Asked by Arushi Juyal 12th November 2017, 4:07 PM
Answered by Expert
Answer:
When the molecule can be divided into equal halves, i.e., the molecule has symmetry and the number (n) of asymmetric carbon atoms is even, then
The no. of optically active forms a = 2(n-1) and the no.of meso forms, m = 2(n-2)-1
Therefore, the total no. of optically active isomers = a + m
                                                                         = 2(n-1) + 2(n/2)-1
 
For butan-2,3-diol , n= 2, a=2(2-1)  =21  =  2
                                      m= 2(n/2)-1 = 2(2/2-1) = 20 =1
 
So,the total optical isomers = 2+1 =3
                                              
Answered by Expert 13th November 2017, 2:45 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Chat with us on WhatsApp