How many optically active stereoisomers are possible for butan-2,3-diol?
Asked by Arushi Juyal
12th November 2017,
4:07 PM
Answered by Expert
Answer:
When the molecule can be divided into equal halves, i.e., the molecule has symmetry and the number (n) of asymmetric carbon atoms is even, then
The no. of optically active forms a = 2(n-1) and the no.of meso forms, m = 2(n-2)-1
Therefore, the total no. of optically active isomers = a + m
= 2(n-1) + 2(n/2)-1
For butan-2,3-diol , n= 2, a=2(2-1) =21 = 2
m= 2(n/2)-1 = 2(2/2-1) = 20 =1
So,the total optical isomers = 2+1 =3
Answered by Expert
13th November 2017,
2:45 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
