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how many moles of pbcl2 formed

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Asked by ashutosharnold1998 14th April 2020, 12:01 PM
Answered by Expert
Answer:
The moles of lead(II) chloride formed can be calculated as:
 

The space reaction space equation space is space as colon

PbO plus space 2 HCl space rightwards arrow space PbCl subscript 2 space plus space straight H subscript 2 straight O

Atomic space weight space of space PbO space equals space 222.9

Atomic space weight space of space HCl equals space 36.5

No. space of space moles space equals space fraction numerator weight space over denominator Molecular space weight end fraction

No. space of space moles space of space PbO space equals space fraction numerator 6.5 over denominator 222.9 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.03

No. space of space moles space of space HCl equals fraction numerator 3.2 over denominator 36.5 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.08

From space this space we space came space to space know space that space limiting space agent space is space PbO.

therefore space Amount space of space PbCl subscript 2 space space formed space is space determined space by space PbO.

1 space mole space of space PbO space gives space 1 space mole space of space PbCl subscript 2.

therefore space 0.03 space moles space oof space PbO space will space give space 0.03 space moles space of space PbCl subscript 2
 

Answered by Expert 14th April 2020, 7:33 PM
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