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How many liters of water will have to be added to 1125 liters of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

Asked by Topperlearning User 12th September 2016, 10:05 PM
Answered by Expert
Answer:

Let us assume that l liters of water is added to 1125 liters so that the resulting mixture contain more than 25% but less than 30% acid solution.

Lets first calculate the acid content in 1125 liters (45% acid).

i.e., liters

Now when l liter of solution is added so the volume becomes (1125 + l) liter.
  Now according to question the acid content should be more than 25% but less than 30% so

 

Now this can be written as two inequalities,

 and

Multiplying by 100

25 l less than fraction numerator 1125 cross times 20 over denominator blank end fraction
l less than fraction numerator 1125 cross times 20 over denominator 25 end fraction
l less than 900

Solving 2nd inequality

then    

Hence the quantity of water added should be greater than 562.5 litre but less than 900.

Answered by Expert 13th September 2016, 12:05 AM
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