How many liters of water will have to be added to 1125 liters of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?
Let us assume that l liters of water is added to 1125 liters so that the resulting mixture contain more than 25% but less than 30% acid solution.
Lets first calculate the acid content in 1125 liters (45% acid).
Now when l liter of solution is added so the volume becomes (1125 + l) liter.
Now according to question the acid content should be more than 25% but less than 30% so
Now this can be written as two inequalities,
Multiplying by 100
Solving 2nd inequality
Hence the quantity of water added should be greater than 562.5 litre but less than 900.
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