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CBSE Class 10 Answered

how many grams of oxygen is required to burn 40 g of sulphur  
Asked by nathsantanukumar | 30 Oct, 2018, 08:49: AM
answered-by-expert Expert Answer
The chemical equation is;
 
space straight S subscript open parentheses straight s close parentheses end subscript space space plus space space straight O subscript 2 subscript open parentheses straight g close parentheses end subscript space space space rightwards arrow space space SO subscript 2 subscript open parentheses straight g close parentheses end subscript space space

space 32 space space space space space space open parentheses 16 cross times 2 close parentheses space space space space space space open parentheses 32 plus 32 close parentheses

32 space straight g space of space sulphur space requires space 32 space straight g space of space oxygen

therefore space 40 space of space sulphur space will space require space fraction numerator 40 cross times 32 over denominator 32 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 40 space of space oxygen
40 g of oxygen is required to burn 40 g of sulphur
 
 
Answered by Varsha | 30 Oct, 2018, 11:39: AM
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