CBSE Class 12-science Answered
How many electrons should be removed from a coin of mass 3.2 g, so that it just float in an electric field of intensity 1010 NC-1, directed upward.
Asked by Topperlearning User | 17 Apr, 2015, 12:46: PM
Expert Answer
Here, m = 3.2g = 3.2 10-3 kg
E = 1010 NC-1
Let n be the number of electrons removed from the coin. Then the charge on the coin is,
q = +ne
When the coin just floats,
Upward force of electric field = weight of the coin
nqE = mg
Answered by | 17 Apr, 2015, 02:46: PM
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