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CBSE Class 12-science Answered

HOW CAN THE OUTPUT RESISTANCE BE HIGH?
Ro=Vce/Ic
here Ic is in order of 10^-3 amperes then when we divide it would become a constant * 10^3 ohms
then too it is given that the resistance will be in the order of 10^5 ohms
pls give the answer as soon as possible iam greatly confused.
Asked by Shiva Raman | 14 Nov, 2014, 05:33: AM
answered-by-expert Expert Answer
The output resistance is given as

begin mathsize 14px style straight r subscript 0 equals open parentheses ΔV subscript CE over ΔI subscript straight C close parentheses end style
Here, VCE is the collector-emitter voltage.
This voltage is applied in reverse biased state. So, in order for transistor to work IC should be large enough.
In other words, we can say that since the collector-emitter junction is reverse biased, it offers a large resistance to the flow of current.
Hence, the output resistance will be very high.
 
Now, if VCE = 10 V and initially IC = 0.1 A, then we have
 
begin mathsize 14px style straight r subscript 0 equals fraction numerator 10 over denominator 0.1 cross times 10 to the power of minus 3 end exponent end fraction equals 1 cross times 10 to the power of 5 space straight capital omega end style
Hence, the higher order of resistance is due to reverse bias of the collector-emitter junction.
Answered by Romal Bhansali | 14 Nov, 2014, 10:38: AM
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