how can i solve this numerical?
Asked by pukai7229
16th May 2018,
9:28 AM
Answered by Expert
Answer:
The stone is projected upwards with speed u =10 m/s.
The height h it reaches from the point of projection is calculated as below
h = u2/(2g) = 10×10/(2×10) = 5 m
time taken th to reach the maximum height :- th = u/g = 10/10 = 1 s.
From the heighest point where it has reached, the stone has to fall a height of 45m to reach ground. Time taken t for falling this 45 m height is calculated as below
45 = (1/2)×10×t2 ; this gives t = 3 s ; total time from the instance of projection of stone to the instance of reaching ground is (3+1) = 4 s;
To pass through the point of projection, when the stone travel from maximum height it has reached, the distance to be travelled is 5 m.
time taken tp to travel this distance 5 m during downward motion is calculated as
5 = (1/2)×10×tp×tp ; this gives tp = 1 second.
Since initially the stone has taken 1 s to reach maximum height, it will pass the projection point during its downward fall after 2 s from the instance of projecting the stone upward.
To get the speed of stone vg when it is striking the ground is calculated as below
vg2 = 2×g×(h+40) = 2×10×45 ; this gives vg = 30 m/s
Answered by Expert
16th May 2018,
12:42 PM
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