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CBSE Class 12-science Answered

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Asked by jain.pradeep | 25 Apr, 2019, 01:36: PM
answered-by-expert Expert Answer
Let from O particles X and Y are projected horizontally with different speeds at time t =0.
 
horizontal distance xt  moved by a particle in time t is given by,   xt = u×t  ..................(1)
where u is horizontal projection speed.
 
since the particlehaving charge q and mass m experiences an upward acceleration (qE/m) due to electric field E, 
 
its vertical distance yt = (1/2) a t2  = (1/2) (qE/m) t2 ................(2)
 
substituting t from eqn.(1), eqn.(2) is rewritten as,   yt =[  qE / (2 m u2 ) ] xt2  .................(3)
 
Hence from eqn.(3) we see that, vertical displacement yt  for a given horizontal displacement xt is
 
(a) directly proportional to charge q,  (b) inversely proportional to mass m  and (c) inversely proportional to square of projection speed.
 
From the horizontal range shown in figure given in the question, we can realise that projection speed of Y is greater than that of X.
 
Hence we can conclude  (B) Y has greater mass than X ,  (C) X has greater charge than Y
 
 
 
Answered by Thiyagarajan K | 27 Apr, 2019, 06:48: AM

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