CBSE Class 12-science Answered
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Asked by jain.pradeep | 29 Apr, 2019, 09:10: PM
Expert Answer
Qn. 31:- the curve shows it is almost reaching the surrounding temperature 20 °C and change in temperature
keep on decreasing and it is very less at 4 hour. Hence after 8 hours of cooling, temperature will be very near to 20 °C
Qn. 32:-
Energy loss ΔE for change in temperature ΔT is given by ΔE = m×Cp×ΔT ,
where m is mass of water and Cp is specific heat of water
if ΔT = 1°C , then Energy loss per °C, m×Cp = 8×105 J /°C .................(1)
Rate of change of energy loss with repect to time, (ΔE/Δt) = m×Cp×( ΔT/Δt) = 16×106 J/hour ................(2)
from eqn.(1) and (2), Rate of temperature falling, ( ΔT/Δt) = 16×106 / ( 8×105) = 20 °C/hour
Answered by Thiyagarajan K | 30 Apr, 2019, 10:45: AM
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