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Hi

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Asked by rayalalokesh2 8th July 2019, 6:50 PM
Answered by Expert
Answer:
Given:
 
Water = 1 molecule
 
Density = 1g/cm3 
 
Avogadro's no of molecules = Molar mass of water
 
6.22×1023 molecules = 18 gm
 
1 molecule of water = 
 
equals space fraction numerator 1 cross times 18 over denominator 6.022 cross times 10 to the power of 23 end fraction space

equals space 2.98 cross times 10 to the power of negative 23 end exponent space gm
 
We know,
 
Density = Mass over Volume
 
Volume = Mass over Density
 
             equals space fraction numerator 2.98 cross times 10 to the power of negative 23 end exponent over denominator 1 end fraction

equals space 2.98 cross times 10 to the power of negative 23 end exponent space cm cubed
 
The volume of 1 molecule of water is 2.98×10-23 cm3
Answered by Expert 9th July 2019, 11:02 AM
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