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Here in question 3 I am unable to get the velocity from the derivative. Please show me how the velocity is obtained. 
 
 

Asked by Varsneya Srinivas 2nd July 2016, 9:39 AM
Answered by Expert
Answer:
We know that velocity is the rate of change of displacemnet.
Given that
begin mathsize 12px style straight x equals 3 plus 8 straight t plus 7 straight t squared
fraction numerator d straight x to the power of straight n over denominator d straight t end fraction equals straight n space straight x to the power of straight n minus straight i end exponent
Differentiating space the space above space equation space wrt comma space we space get
rightwards arrow fraction numerator d straight x over denominator d straight t end fraction equals fraction numerator d open parentheses 3 close parentheses over denominator d straight t end fraction plus fraction numerator d open parentheses 8 straight t close parentheses over denominator d straight t end fraction plus fraction numerator d open parentheses 7 straight t squared close parentheses over denominator d straight t end fraction
rightwards arrow fraction numerator d straight x over denominator d straight t end fraction equals 8 plus 2 cross times 7 straight t space....... space left parenthesis Equation space 1 right parenthesis
Given space that space straight t space equals space 2 straight s
Substituing space in space equation space left parenthesis 1 right parenthesis comma space we space get
rightwards arrow fraction numerator d straight x over denominator d straight t end fraction equals straight v equals 8 plus 2 cross times 7 cross times open parentheses 2 close parentheses space
rightwards arrow straight v equals 36 space straight m divided by straight s
In space straight a space similar space way comma space acceleration space is space the space rate space of space change space of space velocity. space
end style
Answered by Expert 4th July 2016, 10:30 AM
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