Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Enquiry

9:00am - 9:00pm IST all days.

Business Inquiry (North)

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

Help me in this....Thanks!!

qsnImg
Asked by jhajuhi19 20th June 2019, 12:23 AM
Answered by Expert
Answer:
(A) workdone for the process from stae-1 -> state-2.
 
Pressure at both states are same :-  ( V0 / T0 ) = ( 2V0 / 2T0 )  , hence workdone  P(2V0 - V0 ) = R(2T0 - T0 ) = RT0
 
workdone for the process from stae-2 -> state-3 :-  constant volume process, hence workdone is zero
 
workdone for the process from stae-3 -> state-4
 
Pressure at both states are same :-  ( 2V0 / T0 ) = ( V0 / (T0/2) )  , hence workdone   P(V0 - 2V0 ) =  R( (T0/2) - T0 ) = -RT0/2
 
workdone for the process from stae-4 -> state-1 :-  constant volume process, hence workdone is zero
 
Hence networkdone for  complete cycle, 1->2->3->4->1,  is  (1/2)RT0
 
Hence statement (A) is true
-------------------------------------------------------------------------------------------------------------
 
(B) False
 
process 2->3  and  4->1 are isochoric (constant volume process),
 
where as for processes 1->2  and 3->4,  heat energy |dQ| > 0 , they are not adiabatic
 
--------------------------------------------------------------------------------------------------------------------
 
(C) heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q1->2 = CPΔT  = (5/2)R (2T0 - T0 ) = (5/2)RT0
      heat transfer for processes (2 -> 3) for unit mole of monoatomic gases , Q2->3 = CVΔT  = (3/2)R (2T0 - T0 ) = (3/2)RT0
Hence the ratio = 5/3
 
Hence statement (C) is true
 
--------------------------------------------------------------------
(D)heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q1->2 = CPΔT  = (5/2)R (2T0 - T0 ) = (5/2)RT0
     heat transfer for processes (3 -> 4) for unit mole of monoatomic gases , Q3->4 = CPΔT  = (5/2)R ( (T0/2) - T0 ) = -(5/2)R(T0/2)
Hence the ratio = 2
 
Hence statement (C) is false
Answered by Expert 20th June 2019, 10:13 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp