 Contact
Need assistance? Contact us on below numbers

For Enquiry

9:00am - 9:00pm IST all days.

Business Inquiry (West / East / South)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

022-62211530

Mon to Sat - 10 AM to 7 PM

Help me in this....Thanks!! Asked by jhajuhi19 20th June 2019, 12:23 AM
(A) workdone for the process from stae-1 -> state-2.

Pressure at both states are same :-  ( V0 / T0 ) = ( 2V0 / 2T0 )  , hence workdone  P(2V0 - V0 ) = R(2T0 - T0 ) = RT0

workdone for the process from stae-2 -> state-3 :-  constant volume process, hence workdone is zero

workdone for the process from stae-3 -> state-4

Pressure at both states are same :-  ( 2V0 / T0 ) = ( V0 / (T0/2) )  , hence workdone   P(V0 - 2V0 ) =  R( (T0/2) - T0 ) = -RT0/2

workdone for the process from stae-4 -> state-1 :-  constant volume process, hence workdone is zero

Hence networkdone for  complete cycle, 1->2->3->4->1,  is  (1/2)RT0

Hence statement (A) is true
-------------------------------------------------------------------------------------------------------------

(B) False

process 2->3  and  4->1 are isochoric (constant volume process),

where as for processes 1->2  and 3->4,  heat energy |dQ| > 0 , they are not adiabatic

--------------------------------------------------------------------------------------------------------------------

(C) heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q1->2 = CPΔT  = (5/2)R (2T0 - T0 ) = (5/2)RT0
heat transfer for processes (2 -> 3) for unit mole of monoatomic gases , Q2->3 = CVΔT  = (3/2)R (2T0 - T0 ) = (3/2)RT0
Hence the ratio = 5/3

Hence statement (C) is true

--------------------------------------------------------------------
(D)heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q1->2 = CPΔT  = (5/2)R (2T0 - T0 ) = (5/2)RT0
heat transfer for processes (3 -> 4) for unit mole of monoatomic gases , Q3->4 = CPΔT  = (5/2)R ( (T0/2) - T0 ) = -(5/2)R(T0/2)
Hence the ratio = 2

Hence statement (C) is false
Answered by Expert 20th June 2019, 10:13 AM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10