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Asked by jhajuhi19 | 20 Jun, 2019, 12:23: AM

Expert Answer

(A) workdone for the process from stae-1 -> state-2.

Pressure at both states are same :- ( V₀ / T₀ ) = ( 2V₀ / 2T₀ ) , hence workdone P(2V₀ - V₀ ) = R(2T₀ - T₀ ) = RT₀

workdone for the process from stae-2 -> state-3 :- constant volume process, hence workdone is zero

workdone for the process from stae-3 -> state-4

Pressure at both states are same :- ( 2V₀ / T₀ ) = ( V₀ / (T₀/2) ) , hence workdone P(V₀ - 2V₀ ) = R( (T₀/2) - T₀ ) = -RT₀/2

workdone for the process from stae-4 -> state-1 :- constant volume process, hence workdone is zero

Hence networkdone for complete cycle, 1->2->3->4->1, is (1/2)RT₀

Hence statement (A) is true

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(B) False

process 2->3 and 4->1 are isochoric (constant volume process),

where as for processes 1->2 and 3->4, heat energy |dQ| > 0 , they are not adiabatic

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(C) heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q_1->2 = C_PΔT = (5/2)R (2T₀ - T₀ ) = (5/2)RT₀

heat transfer for processes (2 -> 3) for unit mole of monoatomic gases , Q_2->3 = C_VΔT = (3/2)R (2T₀ - T₀ ) = (3/2)RT₀

Hence the ratio = 5/3

Hence statement (C) is true

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(D)heat transfer for processes (1 -> 2) for unit mole of monoatomic gases , Q_1->2 = C_PΔT = (5/2)R (2T₀ - T₀ ) = (5/2)RT₀

heat transfer for processes (3 -> 4) for unit mole of monoatomic gases , Q_3->4 = C_PΔT = (5/2)R ( (T₀/2) - T₀ ) = -(5/2)R(T₀/2)

Hence the ratio = 2

Hence statement (C) is false

Answered by Thiyagarajan K | 20 Jun, 2019, 10:13: AM

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