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CBSE Class 9 Answered

Hello sir, can you please explain me the statement given below with an example, "acceleration due to gravity on the Moon is one sixth the value on the surface of the Earth" thank you
Asked by seeni2005 | 06 Sep, 2018, 07:40: PM
answered-by-expert Expert Answer
The below is an example that explains that the
"acceleration due to gravity on the Moon is one sixth the value on the surface of the Earth":
 
- It is a factual information that the acceleration due to gravity on the surface of the Moon is about 1.625 m/s2 when compared to the acceleration due to gravity on the surface of the Earth which is 9.8 m/s2 .
- Weight is the force acting on the mass of a body that pulls it downwards due to the gravitational pull of the surface.
- Weight (w) = mass (m) x acceleration due to gravity (g)
- On the surface of the Earth, the weight of a body that has a mass of 10 kg will be
 w = 10 x 9.8 = 98 N
- On the surface of the Moon, the weight of the same body that has a mass of 10 kgs will be
w = 10 x 1.625 = 16.25 N
Comparison of the weight of a body on the Moon with respect to that on the Earth = 16.25/98  = 1/6
- Thus it is proved with this example that the acceleration due to gravity and the weight of any body on the Moon is 1/6th of that on the Earth
Answered by Abhijeet Mishra | 07 Sep, 2018, 11:28: AM

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