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haarshit ..........triangles.........................???///

Asked by 19th February 2009, 6:02 PM
Answered by Expert
Answer:

in triangle ACD ,tanA =CD/AD...(1)
in triangle BCD ,tanB =CD/BD...(2)
Dividing above two eqn,we get:
tanB/tanA=AD/BD=(AC/BC)/(BC/AC)=(AC/BC)2



Answered by Expert 20th February 2009, 12:43 AM
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