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Gold crystallises in ccp structure .total no of voids present in 197 g of gold will be how much

Asked by tandonyashika 7th June 2018, 8:13 PM
Answered by Expert
Answer:
No. of unit cells in ccp = 4
 
Voids in Octahedral + tertrahedral sites = 2n + n = 3n
 
Therefore total voids = 4 X 3 = 12
 
Hence for 1 atom fraction numerator 12 over denominator 4 space end fraction equals space space 3 space N a
Answered by Expert 8th June 2018, 2:58 PM
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