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CBSE Class 9 Answered

give the solution of this question.
Asked by ommishra763 | 26 Feb, 2016, 03:51: PM
answered-by-expert Expert Answer
begin mathsize 12px style It space is space not space possible space to space solve space the space problem space unless space the space rhombus space is space straight a space square. So space assuming space that space the space given space rhombus space is space straight a space square comma space we space space proceed space as space follows colon triangle ABM approximately equal to triangle BCL rightwards double arrow angle LBC equals angle MAB equals straight theta Let space the space point space of space intersection space of space AM space and space BL space be space apostrophe straight O apostrophe angle ABO equals 90 degree minus angle LBC equals 90 degree minus straight theta In space triangle ABO comma space angle BAO equals straight theta space and space angle ABO equals 90 degree minus straight theta rightwards double arrow angle BOA equals 90 degree rightwards double arrow BL perpendicular AM...... left parenthesis 1 right parenthesis Area space of space triangle BLC equals Area space of space triangle space AMB rightwards double arrow Area space of space triangle BOM plus Area space of space square MOLC equals Area space of space triangle BOM plus Area space of space triangle AOB rightwards double arrow Area space of space square MOLC equals Area space of space triangle AOB.... left parenthesis 2 right parenthesis triangle AOB tilde triangle ABM rightwards double arrow AO over AB equals OB over BM equals AB over AM rightwards double arrow fraction numerator AO cross times OB over denominator AB cross times BM end fraction equals open parentheses AB over AM close parentheses squared rightwards double arrow AO cross times OB equals AB cross times BM cross times fraction numerator AB squared over denominator AB squared plus BM squared end fraction rightwards double arrow AO cross times OB equals 10 cross times 5 cross times 100 over 125 equals 40 therefore Area space of space triangle AOB equals 1 half cross times AO cross times OB equals 20 space sq. space cm From space left parenthesis 2 right parenthesis comma space area space of space shaded space part equals area space of space square MOLC equals Area space of space triangle AOB equals 20 space sq. space cm end style
Answered by satyajit samal | 29 Feb, 2016, 01:39: AM

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CBSE 9 - Maths
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