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CBSE Class 12-science Answered

integral square root of sin to the power of negative 1 end exponent open parentheses cos x close parentheses end root d x space equals space ? e x p l a i n
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Asked by modi72879 | 11 Nov, 2017, 06:36: PM
answered-by-expert Expert Answer
begin mathsize 16px style sin to the power of negative 1 end exponent left parenthesis cosx right parenthesis equals straight pi over 2 minus cos to the power of negative 1 end exponent left parenthesis cosx right parenthesis equals straight pi over 2 minus straight x integral space becomes integral square root of straight pi over 2 minus straight x end root space dx put space straight pi over 2 minus straight x equals straight t and space solve end style
Answered by Arun | 07 Dec, 2017, 12:32: PM

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