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CBSE Class 9 Answered

Give an application of Newton’s second law of motion. An object having mass 150g and moving with a speed of 18 m/s collides with a wall and returns back along its original path with a speed of 12 m/s. Calculate the rate of change of momentum of this object. Given the object was in contact with the wall for 0.2 sec.
Asked by 140285saksham | 18 Feb, 2021, 08:07: PM
answered-by-expert Expert Answer
When an object of mass m is subjected to net force F , then the object will move with acceleration a that is given by
 
F = m × a
 
Above equation represents Newton's second law of motion.
 
Hence from above equation if force is known , we get acceleration of mass m
 
If acceleration is known, then we get force acting on mass m.
 
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 Second part of question
 
Rate of change of momentum = Change in momentum / time
 
change in momentum = mass × Change in velocity = 0.150 × [ -12 -18 ] = -4.5 kg m/s
 
( Let us consider direction of initial speed is +ve , hence direction returning motion is -ve )
 
Rate of change of momentum = -4.5 / 0.2 = -22.5 N
Answered by Thiyagarajan K | 18 Feb, 2021, 10:44: PM
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