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# Ghazipur, Uttar Pradesh 233001, India

Asked by as23072000 18th September 2021, 7:12 AM
Radius of curvature of mirror , R = 10 cm

Focal length f = 5 cm

wire is placed at u = 20 cm

we have mirror equation , ( 1/v) + (1/u) = 1/f

where v is mirror-to-image distance

1/v = (1/5) - (1/20) = 3/20

Hence , mirror to image distance = (20/3) cm = 6.67 cm

Magnitude of magnification = v/u = (20/3) / 20  = (1/3)

If the plane of L-shaped wire is facing the mirror directly , then magnification of vertical side and horizontal side is same.
In that case , image size of horizontal side and that of verical side is same.

Image size is (1/3) of size of either vertical or horizontal length of wire .
Answered by Expert 18th September 2021, 8:14 AM
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