Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Functions
Asked by arvind95 | 26 Jul, 2012, 07:41: PM
answered-by-expert Expert Answer
It is given that p, q, r are roots of the equation f(x) = 0
So, f(p) = f(q) = f(r) = 0
 
Therefore,
ap3 + bp2 + cp + d = 0
aq3 + bq2 + cq + d = 0
ar3 + br2 + cr + d = 0
 
Adding the above three equations, we get,
a(p3 + q3 + r3) + b(p2 + q2 + r2) + c(p + q + r) + d = 0
a(p3 + q3 + r3) + b[(p + q + r)2 - 2(pq + qr + pr)] + c(p + q + r) + d = 0            ... (1)
 
Also, we have:
p + q + r = -b/a
pq + qr + pr = c/a
pqr = -d/a
 
On substituting these values in equation (1), you will get p3 + q3 + r3 in terms of a, b, c and d.
Answered by | 01 Aug, 2012, 10:13: AM
CBSE 12-science - Maths
Asked by 20muskaansharma23 | 08 Apr, 2024, 11:31: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by nainaadityathakur | 12 Mar, 2024, 01:22: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by jhaprabhat920 | 05 Feb, 2024, 10:33: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by raunakumar9300 | 01 Feb, 2024, 04:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by amandwivesh | 25 Oct, 2023, 11:57: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by bornalimalakar3 | 05 Oct, 2023, 11:15: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by sdmbotch1123 | 19 Sep, 2023, 01:53: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by iamujjy | 21 May, 2023, 04:55: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×