1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

From a metal sheet of diamention 48*36 cm sq of side 8cm is cut out and folded along the edge to form an open container. Find the volume of container so developed.

Asked by 10th March 2013, 11:14 PM
Answer : Given :A metallic sheet is of the rectangular shape with dimensions 48cm x 36cm . From each of its corners a square of side 8cm is cut off . An open box is made of the remaining sheet .

To Find : the volume of the box formed.

After taking the square out of each sides,
the length of the sides are as follows (from figure above)
KL= EF= HG=PR= 48-8-8=32cm
IO=EH=FG=JQ=36-8-8=20cm
KE=LF=HP=GR= 8cm (sides of the square teared out)
The length of the box would be KL = 32 cm.
The width of the box =JQ = 20 cm
and the heigth would be after folding the sides = JF = 8 cm
Volume= length*width*ht
Therefore the net volume = 32*20*8 = 5120cm3 Ans
Answered by Expert 11th March 2013, 12:04 AM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10