CBSE Class 9 Answered
fourth equation of motion with respect to distance and time
Asked by bymks.220 | 15 Mar, 2019, 06:47: PM
Expert Answer
It's given as
s = u×t + 1/2 a×t^2
Where s is the distance/displacement
u is initial velocity
a is acceleration
t is time taken.
Answered by Ankit K | 15 Mar, 2019, 07:12: PM
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