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Four cells of 2 volts each re connected in series with an ammeter, a resistor of 6 ohms and another unknown resistor .A voltmeter is also connected across both resistors.The  current flowing through the circuit is 2 Amps.Draw the circuit and find the current through both the resistors as well as the potential difference  across them.
Asked by bcnandi | 13 May, 2019, 09:37: PM
answered-by-expert Expert Answer
 
 
According to the question,
 
Voltage in the circuit = 2 x 4 = 8 V 
 
As the current of 2 A is flowing throught the circuit the resistors must be connected in parallel to each other. 
 
Thus, by using Ohm's law,
The current flowing through 6 Ω resistor is 
V = IR 
8 = I x 6
I  = 8/6 = 4/3 A 
 
Thus current flowing through unknown resistor is,
 
Thus, the unknown resistor is,
 
 I subscript R space equals space 2 space minus space 4 over 3 space equals space 2 over 3 T h u s comma space t h e space u n k n o w n space r e s i s t o r space i s comma R space equals space fraction numerator V over denominator I subscript R space end fraction R space equals fraction numerator 8 over denominator begin display style bevelled 2 over 3 end style end fraction R space equals space fraction numerator 8 space cross times space 3 over denominator 2 end fraction equals 12 space capital omega
 
Thus, current through 6 ohm resistor is 4/3 A = 1.3 A 
And current through unknown resistor = Total current in circuit - current through 6 ohm resistor = 2 - 1.3 = 0.7 A 
 
The potential difference across both the resistor is 8 V. 
Answered by Shiwani Sawant | 14 May, 2019, 03:52: PM

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